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A steel bowl is hemispherical in shape and 0.5 cm thick. The bowl's internal radius is 4 cm. How much steel was used to make the bowl?

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55.833 cm 3

56.833 cm 3

56.533 cm 3

55.533 cm 3

answer is B.

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Detailed Solution

Given that, the hemispherical steel bowl's internal radius,

r = 4 c m

and 0.5 cm is the thickness of steel.

∴ R − r = 0.5 cm

Thus, the external radius can be calculated as,

R − 4 = 0.5 ⇒ R = 4.5 cm

We know that the volume of the hollow hemisphere is

23 π R 3 − 23 π r 3,

where r is the internal radius and R is the external radius of the hemisphere.
Now, the volume of steel bowl can be calculated as,
Question Image

Therefore the volume of the steel is

56.833 cm 3 .

Hence, option (2) is correct.

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