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A steel rod of dimensions $4 \times 4 {cm}^{2}$ is tightly fixed between two supports and is not allowed to expand. It is heated through 4⁰C. Thermal stress developed is ------10⁶ N/m². $(Y = 20 \times 10^{10} N / m^{2}, α = 11 \times 10^{- 6} /^{0} C)$

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7.2

3.6

8.8

2.7

answer is C.

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Detailed Solution

Thermal stress: $(\frac{F}{A}) = Yα (∆ T) = 20 \times 10^{10} \times 11 \times 10^{- 6} \times 4 = 88 \times 10^{5} = 8.8 \times 10^{6} N / m^{2}$

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