A steel wire having radius of 2mm carrying a load of 4kg is hanging from a ceiling (given $g = 3.1 π {ms}^{- 2}$ ) what will be the tensile stress that would develop in the wire

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$5.2 \times 10^{6} {Nm}^{- 2}$

$4.8 \times 10^{6} {Nm}^{- 2}$

$3.1 \times 10^{6} {Nm}^{- 2}$

$6.2 \times 10^{6} {Nm}^{- 2}$

answer is D.

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Detailed Solution

$Tensile stress = \frac{Tensile force}{Cross - sectional area} = \frac{mg}{{πR}^{2}} = \frac{4 \times 3.1 π}{π \times 4 \times 10^{- 6}} = 3.1 \times 10^{6} {Nm}^{- 2}$

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