A steel wire of diameter 1mm and length 2 m is stretched by a force of 2kgwt. Then the elongation is nearly ------- x10^-4m. (Y_s = 2x10¹¹)

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Detailed Solution

$e = \frac{F \cdot l}{{πr}^{2} y} = \frac{2 X 9.8 X 2}{π \times {(\frac{1}{2} \times 10^{- 3})}^{2} \times 2 \times 10^{11}} \approx 2.5 \times 10^{- 4} m$

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