Q.

A steel wire of length 3.2mYS=2.0×1011Nm2 and a copper wire of length 4.4 mYC=1.1×1011Nm2, both of radius 1.4 mm are connected end to end. When stretched by a load, the net elongation is found to be 1.4 mm. The load applied, in Newton, will be:  Given π=227

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a

1080

b

180

c

360

d

154

answer is D.

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Detailed Solution

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Δℓ1+Δℓ2=ΔℓFℓ1A1y1+Fℓ2A2y2=ΔℓF=Δℓ1A1y1+2A2y2=1.54×102=154

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A steel wire of length 3.2mYS=2.0×1011Nm−2 and a copper wire of length 4.4 mYC=1.1×1011Nm−2, both of radius 1.4 mm are connected end to end. When stretched by a load, the net elongation is found to be 1.4 mm. The load applied, in Newton, will be:  Given π=227