A steel wire of radius 0.2 mm is stretched by applying a force of 36 N. Find the stress in the wire.

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$28.6 \times 10^{8} N m^{- 2}$

$2.866 \times 10^{8} N m^{- 2}$

$58.6 \times 10^{4} N m^{- 2}$

$4.2 \times 10^{7} N m^{- 2}$

answer is A.

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Detailed Solution

$r = 0.2 m m = 0.2 \times 10^{- 3} m, F = 36 N$ $s t r e s s = \frac{F}{A} = \frac{F}{π r^{2}} = \frac{36}{3.14 {(0.2 \times 10^{- 3})}^{2}} = 286.6 \times 10^{6}$ $= 2.866 \times 10^{8}$

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