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A step down transformer connected to an ac mains supply of 220 V is made to operate at 11 V, 44 W lamp. Ignoring power losses in the transformer, what is the current in the primary circuit ?

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4 A

0.2 A

0.4 A

2 A

answer is B.

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Detailed Solution

V_P = 220 V_S = 11 V P = 44 W
As it is an ideal transformer
$\begin{array}{l} V_{P} i_{P} = V_{S} i_{s} = 44 W \\ 220 \times i_{p} = 44 \\ i_{p} = \frac{44}{220} = \frac{1}{5} = 0 .2 A \end{array}$

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