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Q.

A step-up transformer operates on a 200 V line and supplies to a load of 2 A. The ratio of primary to secondary windings is 1 : 25. The primary current is

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a

8.8 A

b

0.08 A

c

12.5 A

d

50 A

answer is D.

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Detailed Solution

Given that n_p / n_s = 1/25,
$E_{p} = 200 V and I_{S} = 2 A$
We know that
$\frac{E_{S}}{E_{p}} = \frac{n_{S}}{n_{p}} or E_{s} = 200 \times 25 = 5000 V$
Now, Input power = output power
$\begin{array}{l} E_{s} \times I_{s} = E_{p} I_{p} \\ 5000 \times 2 = 200 \times I_{p} \\ or I_{p} = 50 A \end{array}$

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