A step-up transformer operates on a 230V line and a load current of 2 A. The ratio of the primary and secondary windings is 1:25. The current in the primary winding (in ampere) is_____

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answer is 50.

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Detailed Solution

Using the relation $\frac{N_{P}}{N_{S}} = \frac{I_{S}}{I_{P}} : I_{P} = \frac{N_{S} I_{S}}{N_{P}}$ Here $\frac{N_{P}}{N_{s}} = \frac{1}{25} (or) \frac{N_{s}}{N_{p}} = \frac{25}{1} = 25$

and $I_{S} = 2 A$ Current in primary, $I_{P} = 25 \times 2 = 50 A$

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