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Q.

A step up transformer operates on a 230V line and a load current of 2 ampere. The ratio of the primary and secondary windings is 1:25 what is the current in the primary?

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a

40A

b

20A

c

50A

d

30A

answer is D.

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Detailed Solution

$\frac{N_{P}}{N_{S}} = \frac{I_{S}}{I_{P}} (o r) I_{P} = \frac{N_{S} I_{S}}{N_{P}}$

$\frac{N_{P}}{N_{S}} = \frac{1}{25} (o r) \frac{N_{S}}{N_{P}} = \frac{25}{1} & I_{S} = 2 A$ and $I_{S} = 2 A$

$∴$ current in primary $I_{P} = 25 \times 2 = 50 A$

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