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Q.

A stone falls freely under gravity. It covers distance h1, h2 and h3. In first 5 sec, next 5 sec and next 5 sec respectively. The relation between h1, h2 and h3 is

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a

h1=2h2=3h3

b

h2=2h1 and h3=3h2

c

h1=h23=h35

d

h1=h2=h3

answer is A.

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Detailed Solution

From the question

h1​ = 1/2gt2 = 1/2​×10×52 = 125

h2 ​= 1/2​×10×102 − 1/2​×10×52 = 375

h3 ​= 1/2×10×152 − 1/2​×10×102 = 625

Hence h1​ = h2​/3​= h3/5​​
 

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