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Q.

A stone falls from a balloon that is descending at a uniform rate of $12 {ms}^{- 1}$ . The displacement of the stone from the point of release after 10 seconds

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a

725 m

b

490 m

c

510 m

d

610 m

answer is C.

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Detailed Solution

Initial velocity

u = 12 {ms}^{- 1}

, Distance travelled s =? ; Time taken t = 10s

$s = ut + \frac{1}{2} a t^{2}$

$\Rightarrow s = 12 (10) + \frac{1}{2} (9.8) (^{50} 100)$

$= 120 + 490 = 610$

$h = 610 m$

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