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A stone is dropped from a certain height which can reach the ground in 5 s. It is stopped after 3 s of its fall and then it is again released. The total time taken by the stone to reach the ground will be

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7 sec

7.5 sec

6 sec

6.5 sec

answer is C.

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Detailed Solution

$h = \frac{1}{2} \times 10 \times {(5)}^{2} = 125 m$ .

$h_{1} = \frac{1}{2} \times 10 \times {(3)}^{2} = 45 m$ .

Rest 80 m is covered in $t = \sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 \times 80}{10}} = 4$

Hence, total time taken is 3s + 4s = 7s

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