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A stone is dropped from a tower with no initial velocity. It is observed that it strikes the ground after $5$ seconds. Which of the following would the velocity impact?

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49 m s^{- 1}

4.9 m s^{- 1}

0.49 m s^{- 1}

0.049 m s^{- 1}

answer is A.

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Detailed Solution

The velocity impact (final velocity) is

49 m s^{- 1}

.
Initial velocity of first stone

u = 0 m s^{- 1}

Time taken for the stone to reach the ground

t = 5

s
Acceleration due to gravity

g = 9.8 m s^{- 2}

We are asked to find the final velocity

v

With the given data we can use the equation

v = u + at

Here we can write the above equation as

v = u + gt - - - - (i)

Substituting all the values in the equation (i), We get

v = 0 + 9.8 \times 5

\Rightarrow v = 49 m s^{- 1}

Thus, the velocity impact or the final velocity is

49 m s^{- 1}

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