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A stone is dropped from the edge of a roof. Which of the following would be the velocity of the stone at a distance of $7.9 m$ ?

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12.44 m s^{- 1}

15.44 m s^{- 1}

124.4 m s^{- 1}

14 m s^{- 1}

answer is A.

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Detailed Solution

The velocity of the stone at a distance of

7.9 m

12.44 m s^{- 1}

.
The stone is not under the influence of anything else other than gravitational force. So we can find all the required details under the consideration of free fall of a body.
Distance traveled

S = 7.9 m

Acceleration due to gravity

g = 9.8 m s^{- 2}

Initial velocity

u = 0 m s^{- 1}

Here we are asked to find the final velocity of the stone at a distance of

7.9 m

.
Final velocity of the stone is v.
We know that

v^{2} = u^{2} + 2 as

Here a is equal to g so we can write

v^{2} = u^{2} + 2 gS - - - - (i)

Substitute the values in the equation (i)

v^{2} = 0^{2} + 2 \times 9.8 \times 7.9

= > v^{2} = 154.84

= > v = 12.44 m s^{- 1}

Thus the velocity of the stone when it reaches a distance of

7.9 m

12.44 m s^{- 1}

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