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Q.

A stone is dropped from the top of a tower of height h=60m. Simultaneously another stone is projected vertically upwards from the foot of the tower. They meet at a height 2h3 from the ground level. The initial velocity(ms–1) of the stone projected upwards is (g=10ms–2)

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answer is 30.

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Detailed Solution

Time taken by upper stone to cover h/3 = 20 m is 2 sec

Time by lower stone to cover 40 m = 2 sec

Finding initial velocity

H = ut - 1/2 gt2

40 = u(2) - 1/2(10)(2)2

u = 30 m/s
 

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