A stone is projected at angle $30^{o}$ to the horizontal. The ratio of kinetic energy of the stone at point of projection to its kinetic energy at the highest point of flight will be.

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1:4

4:3

1:2

4:1

answer is B.

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Detailed Solution

Kinetic Energy at point of projection, $K_{1} = \frac{1}{2} {mu}^{2}$

K.E at highest point is $K_{2} = \frac{1}{2} m (ucos θ)^{2}$
$∴ \frac{K_{1}}{K_{2}} = \frac{1}{\cos^{2} θ} = \frac{1}{\cos^{2} 30^{\circ}} = \frac{4}{3}$

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