A stone is projected from the ground with a velocity of $14m{s}^{–1}$. One second later it clears a wall 2 m high. The angle of projection is $(g=10m{s}^{–2})$

So the ball has risen by a distance of 2m in first two seconds,

$\mathrm{y}=\left(\mathrm{usin\theta }\right)\mathrm{t}-\frac{1}{2}{\mathrm{gt}}^2$

$2=\left(\mathrm{usin\theta }\right)-\frac{1}{2}\left(10\right).{\left(1\right)}^2\Rightarrow \mathrm{usin\theta }=7$.

We know initial speed is 14ms^-1.

So, $\mathrm{sin\theta }=\frac{1}{2}\Rightarrow \mathrm{\theta }={30}^{\mathrm{o}}$