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Q.

A stone is projected from the ground with a velocity of 14 ms−1 one second later it clears a wall 2m high. The angle of projection is (g=10 ms−2)

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a

15°

b

30°

c

60°

d

45°

answer is B.

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Detailed Solution

y=uyt−12gt2

y=usinθt−12gt2

y=14sinθ(1)−12×10×1

2+5=14sinθ

sinθ=714=12

θ=30°

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