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A stone is projected from the ground with a velocity of 14 ms^–1 . one second later it clears a wall 2 m high. The angle of projection is (g = 10 ms^–2)

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answer is B.

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Detailed Solution

$\begin{array}{l} y = (usin θ) t - \frac{1}{2} {gt}^{2} \\ 2 = (14 \sin θ) 1 - \frac{1}{2} \times 10 \times 1 \\ \sin θ = \frac{1}{2} = \sin 30^{\circ} \Rightarrow θ = 30^{0} \end{array}$

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