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A stone is projected horizontally with a speed of 40 m/s from the top of a tower of height 45 m. Then speed of the stone just before it strikes the ground is

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20 m/s

30 m/s

50 m/s

60 m/s

answer is C.

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Detailed Solution

V = Vertical component of velocity

$= \sqrt{2 g h} = \sqrt{2 \times 10 \times 45} m / s = 30 m / s$

u = horizontal component of velocity = 40 m/s

$∴$ speed $= \sqrt{u^{2} + v^{2}} = \sqrt{40^{2} + 30^{2}} m / s = 50 m / s$

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