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A stone is thrown horizontally with velocity g ms^–1 from the top of a tower of height g metre. The velocity with which it hits the ground is (in ms^–1)

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$\sqrt{3}$ g

answer is C.

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Detailed Solution

$V = \sqrt{u^{2} + 2 gH} = \sqrt{g^{2} + 2 g \cdot g} = \sqrt{3 g^{2}} = \sqrt{3} g$

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