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Q.

A stone is thrown in a vertically upward direction with a velocity of $5 m / s$ . If the acceleration of the stone during its motion is $10 m s^{- 2}$ in the downward direction, then what will be the height attained by the stone?

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a

1.2 m

b

1.5 m

c

1.25 m

d

1.3 m

answer is C.

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Detailed Solution

The height attained by the stone is

1.25 m

.
Given,
Initial velocity,

u = 5 m / s

Final velocity,

v = 0 m / s

Acceleration,

a = - 10 m s^{- 2}

From the equations of motion, the relation between initial velocity

(u)

, final velocity

(v)

, distance

(s)

and acceleration

(a)

is given by

v^{2} - u^{2} = 2 \times a \times s

On substituting the respective values we get,

{\Rightarrow 0}^{2} - 5^{2} = 2 \times (- 10) \times s

\Rightarrow - 25 = - 20 s

\Rightarrow s = 1.25 m

Hence, the height attained is

1.25 m

.

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A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 ms-2 in the downward direction, then what will be the height attained by the stone?