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A stone is thrown upwards with a velocity of 50ms^-1. Another stone is simultaneously thrown downwards from the same location with a velocity of 50ms^-1. When the first stone is at the highest point, the velocity of the second stone is (Take g = 10 ${ms}^{- 2}$ )

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Zero

50 ${ms}^{- 1}$

100 ${ms}^{- 1}$

150 ${ms}^{- 1}$

answer is C.

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Detailed Solution

$t = \frac{50}{g} = \frac{50}{10} = 5 s$

v = u + at = 50 +10 $\times$ 5 = 100 m/s

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