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A stone is thrown vertically upward from the top of a tower with a velocity of 10 m/s. If the stone hits the ground after 5 second, the height of the tower is (Take $g = 10 m / s^{2}$ )

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80 m

75 m

60 m

55 m

answer is B.

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Detailed Solution

Considering vertically upward physical quantities negative and vertically downward physical quantities positive, we can write $h = - u t + \frac{1}{2} g t^{2} = - 10 \times 5 + \frac{1}{2} \times 10 \times 5^{2} m = 75 m$

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