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A stone is thrown vertically upward with a speed of 10.0 ms^-1 from the edge of a cliff 65 m high. What will be its speed just before hitting the bottom?

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3.14m/s

37.14m/s

14.71m/s

13.71m/s

answer is B.

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Detailed Solution

From kinematic equations of motion

v² = u² + 2as

v² = 10² + 2 x(- 9.8) x (-65)

v²= 100 + 19.6 × 65

v² = 1374

v = 37. 14 m/s

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