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A stone is thrown vertically upwards from the ground. When the stone is at a height equal to half of its maximum height, its speed is 10 ms^-1. Then the maximum height reached by the stone is $(g = 10 m s^{- 2})$

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15 m

5 m

10 m

20 m

answer is B.

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Detailed Solution

Let H be the maximum height attainable by the body, then

$0 - u^{2} = - 2 g H \Rightarrow u = \sqrt{2 g H}$

At height H/2,

$v^{2} - u^{2} = - 2 g \frac{H}{2}$

$\Rightarrow 10^{2} - 2 g H = g H$

$\Rightarrow g H = 100 \Rightarrow H = 10 m$

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