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Q.

A stone is thrown with a velocity u making an angle $θ$ with the horizontal. The horizontal distance covered by its fall to ground is maximum when the angle $θ$ is equal to (in degree)

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answer is 45.

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Detailed Solution

Since range on horizontal plane is $R = \frac{u^{2} \sin 2 θ}{g}$ so it is max. When $\sin 2 θ = 1$
$\Rightarrow θ = \frac{π}{4}$

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