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A stone of 1kg is thrown with a velocity of $20 {ms}^{- 1}$ across the frozen surface of a lake and comes torest after travelling a distance of 50 m then the force of friction between the stone and the ice is

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2 N

16 N

4 N

8 N

answer is C.

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Detailed Solution

$ΔKE = W$

$\begin{aligned} \frac{1}{2} {mv}^{2} - \frac{1}{2} {mu}^{2} = F . S \\ 0 - \frac{1}{2} (1) (20)^{2} = F (50) \end{aligned}$

$∴ F = \frac{- 200}{50} = - 4 N$ Where -ve Sign indicates the opposing force

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