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A stone of mass 0.5 kg is attached to a string of length 2 m and is whirled in a horizontal circle. If the string can with stand a tension of 9N, the maximum velocity with which the stone can be whirled is

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$6 m s^{- 1}$

$8 m s^{- 1}$

$4 m s^{- 1}$

$12 m s^{- 1}$

answer is A.

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Detailed Solution

Centripetal force will be provided by the string

Tension, $T = \frac{{mv}^{2}}{r} \Rightarrow 9 = \frac{0.5 {xv}^{2}}{2} \Rightarrow v = 6 m / s$

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