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A stone of mass 1 kg is tied with a string and it is whirled in a vertical circle of radius 1 m. If tension at the highest point is 14 N, then velocity at lowest point will be $(g = 10 m / s^{2})$

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$3 m / s$

$6 m / s$

$4 m / s$

$8 m / s$

answer is D.

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Detailed Solution

$T = \frac{M v_{h}^{2}}{r} - m g$

$14 = 1 \times v_{h}^{2} - 1 \times 10$

$v_{h}^{2} = 24 \to (1)$

$v_{1}^{2} - v_{h}^{2} = 2 g (2 r)$

$v_{1}^{2} = 24 + 20 \times 2$ $= 64$

$v_{1}^{} = 8 m s^{- 1}$

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