A stone of mass 1 kg is ties to end of a massless string of length 1m. If the breaking tension of the string is 400N, then maximum linear velocity, the stone can have without breaking the string, while rotating in horizontal plane, is:

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10 ms^-1

400 ms^-1

20 ms^-1

40 ms^-1

answer is B.

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Detailed Solution

Breaking Tension = 400N
For stone to rotate in horizontal circle without breaking
T $\leq$ Breaking tension
$\begin{array}{l} \frac{{mv}^{2}}{R} \leq 400 \\ \frac{(1) V^{2}}{(1)} \leq 400 \\ V \leq 20 m / s \\ V_{max} = 20 m / s \end{array}$

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