A stone of mass 1kg is tied to one end of a string of length 0.5 m. It is whirled in a vertical circle. If the maximum tension in the string is 58.8N, the velocity at the top is

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3.26 ms^–1

1.82 ms^–1

2.2 ms^–1

2.87 ms^–1

answer is B.

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Detailed Solution

$T = mg + \frac{{mv}^{2}}{r} \Rightarrow 58.8 = 9.8 + \frac{(1) v^{2}}{0.5} \Rightarrow 49 = \frac{v^{2}}{0.5}$

$v^{2} = \frac{49}{2} \Rightarrow v = \frac{7}{1.4} = 5; \sqrt{5 gr} = 5$

$V_{top} = \sqrt{gr} = \frac{5}{\sqrt{5}} = \sqrt{5} = 2.2 m / s$

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