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A stone of mass 5 kg is tied to a string of length 10 m and is whirled round in a horizontal circle. What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of 200 N?

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$10 m s^{- 1}$

$15 m s^{- 1}$

$20 m s^{- 1}$

$25 m s^{- 1}$

answer is C.

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Detailed Solution

Here, $m = 5 k g, r = 10 m, T_{m a x} = 200 N$

As, $T_{m a x} = \frac{m {v^{2}}_{m a x}}{r} ∴ {v^{2}}_{m a x} = \frac{T_{m a x} \times r}{m}$

$∴ {v^{2}}_{m a x} = \frac{200 \times 10}{5} = 400 \Rightarrow v_{m a x} = 20 m s^{- 1}$

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