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A stone of relative density ‘k’ is released from rest on the surface of a lake. If viscous effect are ignored, the stone in water has an acceleration of

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$g (1 - k)$

$g (1 + k)$

$g (1 - \frac{1}{k})$

$g (1 + \frac{1}{k})$

answer is C.

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Detailed Solution

$k = \frac{ρ_{s}}{ρ_{w}}$

$F n e t = m g - F_{B} v ρ_{w} g = \frac{v ρ_{s} g}{k} = \frac{m g}{k}$

$F n e t = m g - \frac{m g}{k}$

$F n e t = m g (1 - \frac{1}{k})$

$m a = m g (1 - \frac{1}{k})$

$a = g (1 - \frac{1}{k})$

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