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A stone thrown upward with a speed u from the top of the tower reaches the ground with a velocity 3u. The height of the tower is

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$3 u^{2} / g$

$4 u^{2} / g$

$6 u^{2} / g$

$9 u^{2} / g$

answer is B.

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Detailed Solution

$v^{2} = u^{2} + 2 a s$

$(3 u)^{2} = u^{2} + 2 (- g) (- h)$

$8 u^{2} = 2 gh$

$h = \frac{4 u^{2}}{g}$

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