A stone tied to the end of a string 100 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 22s, then the acceleration of the stone is

see full answer

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

16 ${ms}^{- 2}$

4 ${ms}^{- 2}$

12 ${ms}^{- 2}$

8 ${ms}^{- 2}$

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Here, r = 100 cm = 1m

Frequency, v = $\frac{14}{22} Hz$

$ω = 2 πv = 2 \times \frac{22}{7} \times \frac{14}{22} = 4 {rads}^{- 1}$

The acceleration of the stone is

$a_{c} = ω^{2} r = {(4)}^{2} (1) = 16$ ${ms}^{- 2}$

Watch 3-min video & get full concept clarity