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Q.

A stone tied to the end of a string 100 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 22s, then the acceleration of the stone is

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a

16 ms-2

b

4 ms-2

c

12 ms-2

d

8 ms-2

answer is A.

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Detailed Solution

detailed_solution_thumbnail

Here, r = 100 cm = 1m

Frequency, v = 1422 Hz

ω = 2πv = 2×227×1422  = 4 rads-1

The acceleration of the stone is

ac = ω2r = (4)2(1) = 16ms-2

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