A stone tied to the end of a string of 1m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone?

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$π$ ² ms^-2 and direction along the radius away from the centre

2 $π$ ² ms^-2 and direction along the radius away from the centre

$π$ ² ms^-2 and direction along the radius towards the centre

2 $π$ ² ms^-2 and direction along the radius towards the centre

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

centripetal acceleration $a_{c} = {rω}^{2} \Rightarrow a_{c} = r 4 π^{2} f^{2}$
$\Rightarrow a_{c} = 1 \times 4 π^{2} \times {(\frac{22}{44})}^{2} \Rightarrow a_{c} = π^{2}$

Direction of centripetal acceleration will also be along the radius.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th