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A Storage battery of emf 8.0V and internal resistance 0.5 $Ω$ is being charged by a 120V dc supply using a series resitor of 15.5 $Ω$ What is the terminal voltage of the battery during charging ?

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11.5V

15.5V

17.5V

14.5V

answer is A.

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Detailed Solution

current in the circuit I = $\frac{(120 - 8)}{(15.5 + 0.5)} = 7 A terminal voltage = 8 + (7 \times 0.5) = 11.5 V$

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