A straight conducting rod of length I and mass m is suspended in a horizontal plane by a pair of flexible strings in a magnetic field of magnitude B. To remove the tension in the supporting strings, the magnitude of the current in the wire is

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mgl/B

mg/lB

lB/mg

mgB/l

answer is C.

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Detailed Solution

If we want strings to have zero tension force, weight of rod should be supported by maximum magnetic force on rod due to magnetic field.
$F_{B} = mg B . I . lsin 90^{\circ} = mg I = \frac{mg}{BI}$

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