A straight, horizontal wire of mass 10mg and length 1m carries a current of $2 A$ . The minimum magnetic required in the region so that so that the magnetic force on the wire may balance its weight is [[1]] $\times 10^{- 5}$ tesla.

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Detailed Solution

A straight, horizontal wire of mass 10mg and length 1m carries a current of

2 A

. The minimum magnetic required in the region so that so that the magnetic force on the wire may balance its weight is

5 \times 10^{- 5} T

Here, mass of the wire,

M = 10^{- 5} kg, I = 2 A, l = 1 m

Then the required magnetic force is,

B = \frac{Mg}{Il}

= \frac{1 0^{- 5} \times 10}{2 \times 1}

= 5 \times 10^{- 5} T

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