A straight line meets the coordinate axes in A and B. Find the equation of the straight line, when (p, q) bisects.

$\text{ Let }\mathrm{a},\mathrm{b}\text{ be the intercepts of the line }\frac{\mathrm{x}}{\mathrm{a}}+\frac{\mathrm{y}}{\mathrm{b}}=1$
This line meets x-axis at A(a, 0)
And y-axis at B(0, b)
$\text{ Mid point of }\overline{\mathrm{AB}}\text{ is }\left(\frac{\mathrm{a}}{2},\frac{\mathrm{b}}{2}\right)=(\mathrm{p},\mathrm{q})$
$\Rightarrow \mathrm{a}=2\mathrm{p},\mathrm{b}=2\mathrm{q}$
$\therefore \mathrm{Equation} \mathrm{of} \mathrm{the} \mathrm{line} \mathrm{is}$
$$\begin{gathered} \frac{\mathrm{x}}{\mathrm{a}}+\frac{\mathrm{y}}{\mathrm{b}}=1 \\ \Rightarrow \frac{\mathrm{x}}{2\mathrm{p}}+\frac{\mathrm{y}}{2\mathrm{q}}=1 \\ \Rightarrow \frac{\mathrm{x}}{\mathrm{p}}+\frac{\mathrm{y}}{\mathrm{q}}=2 \end{gathered}$$