A straight line passes through (4, 5) and makes an angle 600 with the X-axis in the positive direction, its equation is

x−x1cos⁡θ=y−y1sin⁡θθ=600∴x−412=y−532⇒x−4=y−53⇒(x−4)3=y−5

A straight line passes through (4, 5) and makes an angle 600 with the X-axis in the positive direction, its equation is

x−x1cos⁡θ=y−y1sin⁡θθ=600∴x−412=y−532⇒x−4=y−53⇒(x−4)3=y−5

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A straight line passes through (4, 5) and makes an angle 60⁰ with the X-axis in the positive direction, its equation is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$\frac{x - 4}{\sqrt{3}} = y + 5$

$\frac{x - 4}{\sqrt{3}} = 5 - y$

$\frac{x + 4}{\sqrt{3}} = y + 5$

$(x - 4) \sqrt{3} = y - 5$

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\begin{array}{l} \frac{x - x_{1}}{\cos θ} = \frac{y - y_{1}}{\sin θ} \\ θ = 60^{0} \\ ∴ \frac{x - 4}{\frac{1}{2}} = \frac{y - 5}{\frac{\sqrt{3}}{2}} \\ \Rightarrow x - 4 = \frac{y - 5}{\sqrt{3}} \Rightarrow (x - 4) \sqrt{3} = y - 5 \end{array}$