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A straight piece of wire 5 cm long is placed horizontally on the surface of water and gently pulled up. It is found that a force of 7×10^–3 N in addition to weight of wire is required for that purpose, the surface tension of water is

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7 × 10^–2 N/m

7 × 10^–1 N/m

7 × 10^–3 N/m

3.5 × 10^–2 N/m

answer is A.

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Detailed Solution

$\begin{array}{l} Force due surface tension is along the circumference \\ F = 2 Tℓ \Rightarrow 7 \times 10^{- 3} \\ 7 \times 10^{- 3} = 2 (T) \times 5 \times 10^{- 2} \end{array}$

$T = 7 \times 10^{- 2} N / m$

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