A stream of a positively charged particles having qm=2×1011Ckg and velocity v→0=3×107i^ m/s is deflected by an electric field 1.8j^ kV/m. The electric field exists in a region of 10 cm along x direction. Due to the electric field, the deflection of the charge particles in the y direction is __________mm.

y=12Eqmxv02=12×1.8×103×2×101110×10−23×1072=1.89×10141016=2mm

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A stream of a positively charged particles having $\frac{q}{m} = 2 \times 10^{11} \frac{C}{kg}$ and velocity ${\vec{v}}_{0} = 3 \times 10^{7} \hat{i}$ m/s is deflected by an electric field $1.8 \hat{j} kV / m$ . The electric field exists in a region of $10 cm$ along x direction. Due to the electric field, the deflection of the charge particles in the y direction is __________mm.

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Detailed Solution

$\begin{array}{l} y = \frac{1}{2} (\frac{Eq}{m}) {(\frac{x}{v_{0}})}^{2} \\ = \frac{1}{2} \times (1.8 \times 10^{3} \times 2 \times 10^{11}) {[\frac{10 \times 10^{- 2}}{3 \times 10^{7}}]}^{2} \\ = \frac{1.8}{9} \times \frac{10^{14}}{10^{16}} = 2 mm \end{array}$