A stream of electrons from a heated filaments was passed two charged plates kept at a potential difference
V esu. If e and m are charge and mass of an electron, respectively, then the value of h/ $λ$ (where $λ$ is wavelength associated with electron wave) is given by:

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$\sqrt{2 meV}$

2meV

$\sqrt{meV}$

meV

answer is B.

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Detailed Solution

As electron of charge 'e' is passed through 'V' volt, kinetic energy of electron will be eV
$Wavelength of electron wave (λ) = \frac{h}{\sqrt{2 m \cdot K \cdot E}}$
$λ = \frac{h}{\sqrt{2 meV}} \Rightarrow∴ \frac{h}{λ} = \sqrt{2 meV}$

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