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Q.

A stream of water flowing horizontally with a speed of 15 ms-1 gushes out of a tube of cross-sectional area 10-2 m2, and hits a vertical wall normally. Assuming that it does not rebound from the wall, the force exerted on the wall by the impact of water is

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a

1.25×103N

b

2.25×103N

c

3.25×103N

d

4.25×103N

answer is B.

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Detailed Solution

Here ν=15 ms-1 , Area of cross section A=10-2 m2, Density of water ρ=103 kg m-3

Mass of water hitting the wall per second =ρ×A×ν=103 kgm-3×10-2 m2×15 ms-1=150 kgs-1

Force exerted on the wall = Momentum loss of water per second 

=150 kgs-1×15 ms-1=2250 N=2.25×103 N

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A stream of water flowing horizontally with a speed of 15 ms-1 gushes out of a tube of cross-sectional area 10-2 m2, and hits a vertical wall normally. Assuming that it does not rebound from the wall, the force exerted on the wall by the impact of water is