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A strecthed string is divided into two parts with the help of a wedge. The total length of the string is 1m and the two parts differ by 2mm. When sounded together they produced two beats per second. The frequencies of the notes emitted by the two parts are

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501 & 499 Hz

501 & 503 Hz

499 & 497 Hz

answer is B.

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Detailed Solution

$\begin{aligned} l_{1} + l_{2} = 1000 mm, l_{1} - l_{2} = 2 mm \\ so, l_{1} = 501 mm, l_{2} = 499 mm \end{aligned}$
$n_{1} 501 = (n_{1} + 2) 499 \Rightarrow n_{1} = 499 Hz and n_{2} = 501 Hz$

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