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Q.

A string is holding a solid block below the surface of a liquid. The density of liquid is greater than that of solid. The tension in the string is T, when the system is at rest; what will be the tension in the string when the system has upward acceleration a

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a

T_{0} [1 + \frac{a}{g}]

b

T_{0} [1 + \frac{g}{a}]

c

[1 + \frac{a}{g}] \frac{T_{0}}{2}

d

T_{0} [1 - \frac{g}{a}]

answer is C.

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Detailed Solution

Tension in the string = upward thrust – weight of the body

$T_{0} = vg (ρ_{1} - ρ)$

$T = v (a + g) (ρ_{1} - ρ)$

$= vg (1 + \frac{a}{g}) (ρ_{1} - ρ)$

$T = T_{0} (1 + \frac{a}{g})$

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A string is holding a solid block below the surface of a liquid. The density of liquid is greater than that of solid. The tension in the string is T, when the system is at rest; what will be the tension in the string when the system has upward acceleration a