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Q.

A string is wrapped around the rim of a wheel of moment of inertia 0.20 kg m2 and of radius 20 cm. The wheel is free to rotate about its axis and initially it is at rest. The, string is now pulled by a force of 20 N. The angular velocity of the string after 5 s will be

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a

70 rad s−1

b

95rads−1

c

90rads−1

d

100rads−1

answer is D.

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Detailed Solution

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We know that τ=1α…(i) and τ=rF=20100(20)

τ=4Nm

Now from eq. (i)

4 = (0.2) (α)

So α=20rads−2

So from ω=ω0+αt

ω0=0 and t=5 sec. 

So ω=0+20(5)

ω=100rad/sec.

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